The intuitive trap with loot is assuming that 50 attempts at a 2 percent drop is a near-certainty. It is not — it is about 64 percent. This calculator uses the binomial distribution to give you honest odds for any drop rate and attempt count, including how many tries it takes to be reasonably sure.
How it works
Each attempt is an independent trial with success probability p. The key
formulas are:
P(none) = (1 − p)^n
P(at least 1) = 1 − (1 − p)^n
P(exactly k) = C(n,k) × p^k × (1 − p)^(n−k)
expected drops = n × p
attempts for c = ceil( ln(1 − c) / ln(1 − p) )
The last formula inverts the at-least-once equation to tell you how many attempts
reach a chosen confidence c, such as 90 or 99 percent.
Example
A 2 percent drop over 50 attempts gives about a 64 percent chance of at least one, a 27 percent chance of exactly one, and a 36 percent chance of nothing. To hit 90 percent confidence you would need roughly 114 attempts.
Notes
This model assumes a constant, independent drop rate. If your game has a pity counter or bad-luck protection, the odds rise faster than this — switch to the pity calculator. The exactly-k figure is computed in log-space to stay accurate even for large attempt counts.