Valorant Breeding & IV Calculator

Calculate the best IVs and breeding outcomes

Compute the probability that an offspring inherits all your target perfect IVs using the real hypergeometric inheritance model, combine it with nature pass-down odds, and see the expected number of eggs to succeed. Runs in your browser.

How is the inheritance probability calculated?

The inherited IV slots are chosen at random from all stat slots. The chance they include all your target stats is the hypergeometric value C(slots minus target, inherited minus target) divided by C(slots, inherited). It is the probability the random selection covers every target slot.

Breeding for perfect IVs is a numbers game, and knowing the real odds saves you hours of hatching eggs blindly. This calculator uses the actual hypergeometric inheritance model to tell you the chance each egg has all your target IVs, then folds in nature odds and the expected egg count.

How it works

The offspring inherits a fixed number of IV slots, chosen at random from all stat slots. The probability those random slots include every one of your target stats is a hypergeometric draw:

P(all target inherited) = C(slots - target, inherited - target) / C(slots, inherited)

where C(n, k) is the binomial coefficient. Combined with the nature pass-down chance, the per-egg success probability is the product of the two, and the expected number of eggs to succeed is one over that:

combined  = P(IVs) × P(nature)
eggs      = 1 / combined

Example and notes

With the standard 6 IV stats, a Destiny-Knot passing 5 IVs, and a target of 4 perfect IVs, the inheritance chance is C(2, 1) / C(6, 5) = 2 / 6 ≈ 33.3%. If you also need a 50% nature pass-down, the combined chance is about 16.7%, or roughly 6 eggs on average. Note the impossible case: asking for 4 target IVs while only 3 are inherited yields a zero chance, since a single egg cannot pass more perfect IVs than its inherited slot count. Breed in stages — perfect one parent further — to break past that limit.